125x^2-215x+90=0

Solution for 125x^2-215x+90=0 equation:

125x^2-215x+90=0

a = 125; b = -215; c = +90;
Δ = b2-4ac
Δ = -2152-4·125·90
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-215)-35}{2*125}=\frac{180}{250}
=18/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-215)+35}{2*125}=\frac{250}{250}
=1
$